A force \(F = 20 + 10y\) acts on a particle in \(y\)-direction where F is in newton and \(y\) in meter. Work done by this force to move the particle from \(y = 0\) to \(y = 1\) m is :
Work by constant and variable force
Every question from past board papers on Work by constant and variable force, newest paper first. Open any question for its full worked answer.
NEET UG 2019 question paper (official, booklet P1)
Full paper →NEET UG 2016 Phase 2 question paper (official, booklet ZZ)
Full paper →-
A particle moves from a point \((-2\hat i+5\hat j)\) to \((4\hat j+3\hat k)\) when a force of \((4\hat i+3\hat j)\) N is applied. How much work has been done by the force?