Calculate change over temperature for a certain reaction, whose ΔH° is – 60 kJ and ΔS° is –150 JK–1.
Q.2 (vii) Calculate change over temperature for a certain reaction, whose ΔH° is – 60 kJ and ΔS° is –150 JK–1.
1 answer
Best answer
Answer: 400 K
At the change-over temperature ΔG = 0, so \(T = \dfrac{\Delta H}{\Delta S} = \dfrac{-60000\ \text{J}}{-150\ \text{J K}^{-1}} = 400\ \text{K}\). (The reaction is spontaneous below 400 K.)
Doubtly AI
· 28 Oct 2026
AI-verified · Oct 2026
Report
Was this answer helpful?
Thanks for the feedback.
Sign up free to save answers and ask your own doubts
Your answer
Log in or create a free account to answer this question.