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Topic: Valence bond theory, hybridization (s, p, d), resonance· Chemical Bonding and Molecular Structure

Match the compounds given in column I with the hybridisation and shape given in column II and mark the correct option.Column I: (a) XeF_6; (b) XeO_3; (c) XeOF_4; (d) XeF_4Column II: (i) distorted octahedral; (ii) square planar; (iii) pyramidal; (iv)…

Match the compounds given in column I with the hybridisation and shape given in column II and mark the correct option.

Column I: (a) \(XeF_6\); (b) \(XeO_3\); (c) \(XeOF_4\); (d) \(XeF_4\)

Column II: (i) distorted octahedral; (ii) square planar; (iii) pyramidal; (iv) square pyramidal

Code: (a) (b) (c) (d)

1. (i) (iii) (iv) (ii)

2. (i) (ii) (iv) (iii)

3. (iv) (iii) (i) (ii)

4. (iv) (i) (ii) (iii)

1 answer

Best answer

Answer: 1. (i) (iii) (iv) (ii)

Key idea: use VSEPR for each xenon compound.

  • \(\mathrm{XeF_6}\): \(sp^3d^3\), 6 bond pairs + 1 lone pair, distorted octahedral (i).
  • \(\mathrm{XeO_3}\): \(sp^3\), 3 bond pairs + 1 lone pair, pyramidal (iii).
  • \(\mathrm{XeOF_4}\): \(sp^3d^2\), 5 bonds + 1 lone pair, square pyramidal (iv).
  • \(\mathrm{XeF_4}\): \(sp^3d^2\), 4 bonds + 2 lone pairs, square planar (ii).

This gives (i) (iii) (iv) (ii), option 1.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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