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Answer: 2. \(SeF_4\) and \(CH_4\) have same shape.

Key idea: compare VSEPR shapes.

  • \(SO_2\) has \(p\pi\)-\(d\pi\) bonding: correct.
  • \(SeF_4\) is see-saw (4 bond pairs + 1 lone pair), while \(CH_4\) is tetrahedral. Different shapes, so this statement is wrong.
  • \(I_3^+\) is bent: correct.
  • \(PH_5\) and \(BiCl_5\) do not exist: correct.
Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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