1. sp² , sp³ and sp 2. sp , sp² and sp³ 3. sp² , sp and sp³ 4. sp , sp³ and sp²

Answer: 2. sp , sp² and sp³ Key idea: hybridisation = (bond pairs + lone pairs) on N. NO₂^+ : O=N=O, 2 bond pairs, no lone pair, so sp . NO₃^- : 3 sigma bonds, no lone pair, so sp² . NH₄^+ : 4 sigma bonds, so sp³ . Order: sp, sp², sp³ .

Topic: Valence bond theory, hybridization (s, p, d), resonance· Chemical Bonding and Molecular Structure

The hybridizations of atomic orbitals of nitrogen in NO_2^+, NO_3^- and NH_4^+ respectively are

1. \(sp^2\), \(sp^3\) and \(sp\)

2. \(sp\), \(sp^2\) and \(sp^3\)

3. \(sp^2\), \(sp\) and \(sp^3\)

4. \(sp\), \(sp^3\) and \(sp^2\)

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Answer: 2. \(sp\), \(sp^2\) and \(sp^3\)

Key idea: hybridisation = (bond pairs + lone pairs) on N.

\(NO_2^+\): O=N=O, 2 bond pairs, no lone pair, so \(sp\).
\(NO_3^-\): 3 sigma bonds, no lone pair, so \(sp^2\).
\(NH_4^+\): 4 sigma bonds, so \(sp^3\).

Order: \(sp, sp^2, sp^3\).

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The hybridizations of atomic orbitals of nitrogen in NO_2^+, NO_3^- and NH_4^+ respectively are

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