1. sp³ and 4 2. sp³ and 6 3. sp² and 6 4. sp² and 8

Topic: Valence bond theory, hybridization (s, p, d), resonance· Chemical Bonding and Molecular Structure

BF_3 is planar and electron deficient compound. Hybridization and number of electrons around the central atom, respectively are :

1. \(sp^3\) and 4

2. \(sp^3\) and 6

3. \(sp^2\) and 6

4. \(sp^2\) and 8

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Answer: 3. \(sp^2\) and 6

Key idea: \(\mathrm{BF_3}\) has three bond pairs and no lone pair on boron.

Three electron domains give \(sp^2\) hybridisation and trigonal planar shape. Boron contributes 3 electrons, each F shares one: boron has only 6 electrons around it (an incomplete octet, hence electron deficient).

So the answer is \(sp^2\) and 6.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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BF_3 is planar and electron deficient compound. Hybridization and number of electrons around the central atom, respectively are :

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