1. 6×10²⁰ 2. 3.75×10²⁰ 3. 7.48×10²³ 4. 6×10²³

Answer: 2. 3.75×10²⁰ Key idea: charge Q=It , and number of electrons =Q/e . Q=1×60=60\ C n=frac601.60×10⁻¹⁹=3.75×10²⁰ Option 4 ( 6×10²³ ) is just Avogadro's number, which is not what is asked.

Topic: Electrolytic and galvanic cells, electrode potentials· Redox Reactions and Electrochemistry

The number of electrons delivered at the cathode during electrolysis by a current of 1 ampere in 60 seconds is (charge on electron = 1.60×10^-19 C)

1. $6\times10^{20}$

2. $3.75\times10^{20}$

3. $7.48\times10^{23}$

4. $6\times10^{23}$

Doubtly Asked 30 Oct 2026 NEET UG 2016 Phase 2 neet Save WhatsApp Report

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Answer: 2. $3.75\times10^{20}$

Key idea: charge $Q=It$, and number of electrons $=Q/e$.

$$Q=1\times60=60\ \mathrm{C}$$$$n=\frac{60}{1.60\times10^{-19}}=3.75\times10^{20}$$

Option 4 ($6\times10^{23}$) is just Avogadro's number, which is not what is asked.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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The number of electrons delivered at the cathode during electrolysis by a current of 1 ampere in 60 seconds is (charge on electron = 1.60×10^-19 C)

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