1. B/3p 2. 3p/B 3. p/3B 4. p/B

Answer: 3. p/3B Key idea: B=p/Δ V/V , and for a sphere V∝ r³ , so Δ V/V=3Δ r/r . Δ r/r=1/3Δ V/V=p/3B .

The bulk modulus of a spherical object is 'B'. If it is subjected to uniform pressure 'p', the fractional decrease in radius is :

1. \(\frac{B}{3p}\)

2. \(\frac{3p}{B}\)

3. \(\frac{p}{3B}\)

4. \(\frac{p}{B}\)

Doubtly Asked 30 Oct 2026 NEET UG 2017 Practice test neet Save WhatsApp Report

Best answer

Answer: 3. \(\frac{p}{3B}\)

Key idea: \(B=\dfrac{p}{\Delta V/V}\), and for a sphere \(V\propto r^3\), so \(\dfrac{\Delta V}{V}=3\dfrac{\Delta r}{r}\).

\(\dfrac{\Delta r}{r}=\dfrac13\dfrac{\Delta V}{V}=\dfrac{p}{3B}\).

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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