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Answer: 3. more on smaller sphere

For a conducting sphere the potential is \(V=\dfrac{kQ}{R}\), depending only on charge and radius, not on the material.

The charges are equal, so \(V\propto 1/R\). Since \(R_2

Option (3) is correct. Equal potential (option 4) would need equal radii.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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