Let T_1 and T_2 be the energy of an electron in the first and second excited states of hydrogen atom, respectively. According to the Bohr's model of an atom, the ratio T_1 : T_2 is :

1. 9 : 4

2. 1 : 4

3. 4 : 1

4. 4 : 9

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Answer: 1. 9 : 4

In Bohr's model the energy magnitude is \(E_n\propto 1/n^2\).

First excited state is \(n=2\) and second excited state is \(n=3\).

\(\dfrac{T_1}{T_2}=\dfrac{1/4}{1/9}=\dfrac94\), i.e. \(9:4\). Option (1).

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