Topic: Bohr model, energy levels, hydrogen spectrum· Atoms and Nuclei

Match List I with List II.List I (Spectral Lines of Hydrogen for transitions from): A. n_2=3 to n_1=2; B. n_2=4 to n_1=2; C. n_2=5 to n_1=2; D. n_2=6 to n_1=2List II (Wavelengths (nm)): I. 410.2; II. 434.1; III. 656.3; IV. 486.1Choose the correct ans…

Match List I with List II.

List I (Spectral Lines of Hydrogen for transitions from): A. \(n_2=3\) to \(n_1=2\); B. \(n_2=4\) to \(n_1=2\); C. \(n_2=5\) to \(n_1=2\); D. \(n_2=6\) to \(n_1=2\)

List II (Wavelengths (nm)): I. 410.2; II. 434.1; III. 656.3; IV. 486.1

Choose the correct answer from the options given below :

1. A-I, B-II, C-III, D-IV

2. A-II, B-I, C-IV, D-III

3. A-III, B-IV, C-II, D-I

4. A-IV, B-III, C-I, D-II

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Answer: 3. A-III, B-IV, C-II, D-I

Key idea: These are Balmer lines (transitions to \(n=2\)); a larger jump means more energy and a shorter wavelength.

From \(\frac{1}{\lambda}=R\left(\frac14-\frac1{n^2}\right)\), the wavelength falls as \(n\) rises: \(n=3\to 656.3\) nm (H-alpha, red), \(n=4\to 486.1\) nm, \(n=5\to 434.1\) nm, \(n=6\to 410.2\) nm.

So A-III, B-IV, C-II, D-I, which is option 3. The other options break this decreasing order.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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Match List I with List II.List I (Spectral Lines of Hydrogen for transitions from): A. n_2=3 to n_1=2; B. n_2=4 to n_1=2; C. n_2=5 to n_1=2; D. n_2=6 to n_1=2List II (Wavelengths (nm)): I. 410.2; II. 434.1; III. 656.3; IV. 486.1Choose the correct ans…

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