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Topic: Bohr model, energy levels, hydrogen spectrum· Atoms and Nuclei

A model for quantized motion of an electron in a uniform magnetic field B states that the flux passing through the orbit of the electron is n(h/e) where n is an integer, h is Planck's constant and e is the magnitude of electron's charge. According to…

A model for quantized motion of an electron in a uniform magnetic field \(B\) states that the flux passing through the orbit of the electron is \(n(h/e)\) where \(n\) is an integer, \(h\) is Planck's constant and \(e\) is the magnitude of electron's charge. According to the model, the magnetic moment of an electron in its lowest energy state will be (\(m\) is the mass of the electron)

1. \(\frac{he}{\pi m}\)

2. \(\frac{he}{2\pi m}\)

3. \(\frac{heB}{\pi m}\)

4. \(\frac{heB}{2\pi m}\)

1 answer

Best answer

Answer: 2. \(\frac{he}{2\pi m}\)

Key idea: the electron moves in a circle in the field, and the given flux quantization fixes the orbit area.

From \(evB=\dfrac{mv^2}{r}\): \(v=\dfrac{eBr}{m}\), and the period is \(T=\dfrac{2\pi m}{eB}\). Magnetic moment:

$$\mu=IA=\frac{e}{T}\,\pi r^2=\frac{e^2B}{2\pi m}\,\pi r^2=\frac{e^2}{2\pi m}\,(B\pi r^2)$$

Lowest state is \(n=1\), so the flux \(B\pi r^2=\dfrac he\):

$$\mu=\frac{e^2}{2\pi m}\cdot\frac he=\frac{he}{2\pi m}$$

The result does not contain \(B\), so options 3 and 4 are out.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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