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Answer: 4. \(100\,\Omega\)

No deflection means no current in the galvanometer branch, so the potential drop across \(R\) equals the 2 V cell.

  1. Current in the 10 V loop: \(I=\dfrac{10}{400+R}\).
  2. Drop across \(R\): \(IR = 2\), so \(\dfrac{10R}{400+R}=2\).
  3. \(10R = 800+2R \Rightarrow R=100\,\Omega\).

The answer is \(100\,\Omega\).

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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