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Topic: Wheatstone bridge and metre bridge· Current Electricity

A resistance wire connected in the left gap of a metre bridge balances a 10 Ω resistance in the right gap at a point which divides the bridge wire in the ratio 3 : 2. If the length of the resistance wire is 1.5 m, then the length of 1 Ω of the resist…

A resistance wire connected in the left gap of a metre bridge balances a 10 \(\Omega\) resistance in the right gap at a point which divides the bridge wire in the ratio 3 : 2. If the length of the resistance wire is 1.5 m, then the length of 1 \(\Omega\) of the resistance wire is :

1. \(1.0\times10^{-2}\) m

2. \(1.0\times10^{-1}\) m

3. \(1.5\times10^{-1}\) m

4. \(1.5\times10^{-2}\) m

1 answer

Best answer

Answer: 2. \(1.0\times10^{-1}\) m

Metre bridge balance: \(\dfrac{X}{10}=\dfrac{l}{100-l}=\dfrac32\).

$$X=15\ \Omega$$

This 15 \(\Omega\) is the resistance of the whole 1.5 m wire. Length per ohm:

$$\frac{1.5}{15}=0.1\ \text{m}=1.0\times10^{-1}\ \text{m}$$

Answer: option 2.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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