#engineering physics
- Light of wavelength 6000A0 is incident on a slit of width 0.30 mm. The screen is placed 2 m away from the slit. a) position of the first order dark fringe = 4*10⁻³m b)width of the central bright maximum = 8 * 10⁻³ m 1
- In Fraunhofer diffraction pattern due to a single slit, the screen is at a distance of 100 cm from slit & slit is the distance between the central maximum & first order minima is 0.5893 cm 1
- A screen is placed 2 m away from a narrow slit which is illuminated with light of wavelength 6000A0.If the first minimum slit width is 0.24 mm 1
- A slit of width 2μm is illuminated by light of wavelength 6500A0.Calculate the angle at which the first minimum will Answer is 18.9655 1
- Find the half angular width of the central maximum in the Fraunhofer diffraction pattern of a slit of width Find the half angular width of the central maximum in the Fraunhofer diffraction pattern of a slit of width 12 X 10⁻⁵ cm,when illuminated by... 2
- A slit of width 0.16 mm is illuminated by a monochromatic light of wavelength 5600A0 A slit of width 0.16 mm is illuminated by a monochromatic light of wavelength 5600A⁰.Find half angular width of a principal maxima 2
- A single slit diffraction pattern is formed using white light. For what wavelength of light does the A single slit diffraction pattern is formed using white light. For what wavelength of light does the 2nd minimum coincide with the 3rd minim... 2
- A slit of width 'a' is illuminated by white light. For what value of 'a' will the first minima for red light fall A slit of width 'a' is illuminated by white light. For what value of 'a' will the first minima for red light fall at an angle of 300 2