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Topic: Semiconductors· Electronic Devices

A npn transistor is connected in common emitter configuration in a given amplifier. A load resistance of 800 Ω is connected in the collector circuit and the voltage drop across it is 0.8 V. If the current amplification factor is 0.96 and the input re…

A npn transistor is connected in common emitter configuration in a given amplifier. A load resistance of 800 \(\Omega\) is connected in the collector circuit and the voltage drop across it is 0.8 V. If the current amplification factor is 0.96 and the input resistance of the circuit is 192 \(\Omega\), the voltage gain and the power gain of the amplifier will respectively be :

1. 4, 3.84

2. 3.69, 3.84

3. 4, 4

4. 4, 3.69

Doubtly Asked NEET UG 2016 Phase 1 neet Save WhatsApp Report
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Answer: 1. 4, 3.84

Key idea: in common emitter, \(A_v=\beta\dfrac{R_L}{R_i}\) and power gain \(=\beta A_v\). The question uses 0.96 as the current gain \(\beta\) in these formulas.

  1. \(A_v=0.96\times\dfrac{800}{192}=4\).
  2. Power gain \(=0.96\times4=3.84\).

So gains are 4 and 3.84.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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