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Answer: 1. 20 mV

In a CE amplifier, \(V_{out}=I_CR_C\) and \(I_C=\beta I_B\); input voltage is \(V_{in}=I_BR_B\).

  • \(I_C=\dfrac{4}{2000}=2\) mA.
  • \(I_B=\dfrac{I_C}{\beta}=\dfrac{2\ \text{mA}}{100}=20\ \mu\text{A}\).
$$V_{in}=20\times10^{-6}\times1000=20\ \text{mV}$$

Option (1).

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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