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Answer: 2. 150 and 15000

Key idea: in a common emitter amplifier, voltage gain \(A_v=\beta\dfrac{R_C}{R_B}\) and power gain \(=\beta A_v\).

\(A_v=100\times\dfrac{3\ \text{k}\Omega}{2\ \text{k}\Omega}=150\).

Power gain \(=\beta\times A_v=100\times150=15000\).

So voltage gain is 150 and power gain 15000.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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