1. C ₂ H ₅ OH, C ₂ H ₆ , C ₂ H ₅ Cl 2. C ₂ H ₅ Cl, C ₂ H ₆ , C ₂ H ₅ OH 3. C ₂ H ₅ OH, C ₂ H ₅ Cl, C ₂ H ₅ ONa 4. C ₂ H ₅ OH, C ₂ H ₅ ONa, C ₂ H ₅ Cl

Answer: 4. C ₂ H ₅ OH, C ₂ H ₅ ONa, C ₂ H ₅ Cl A is ethanol. C₂H₅OH+Na→ C₂H₅ONa (B), and C₂H₅OH+PCl₅→ C₂H₅Cl (C). B and C then react by Williamson synthesis: C₂H₅ONa+C₂H₅Cl→ C₂H₅OC₂H₅+NaCl . So A, B, C = ethanol, sodium ethoxide, chloroethane.

Topic: Alcohols: identification of 1/2/3 alcohols, dehydration mechanism· Organic Compounds Containing Oxygen

The compound A on treatment with Na gives B, and with PCl_5 gives C. B and C react together to give diethyl ether. A, B and C are in the order

1. C\(_2\)H\(_5\)OH, C\(_2\)H\(_6\), C\(_2\)H\(_5\)Cl

2. C\(_2\)H\(_5\)Cl, C\(_2\)H\(_6\), C\(_2\)H\(_5\)OH

3. C\(_2\)H\(_5\)OH, C\(_2\)H\(_5\)Cl, C\(_2\)H\(_5\)ONa

4. C\(_2\)H\(_5\)OH, C\(_2\)H\(_5\)ONa, C\(_2\)H\(_5\)Cl

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Answer: 4. C\(_2\)H\(_5\)OH, C\(_2\)H\(_5\)ONa, C\(_2\)H\(_5\)Cl

A is ethanol. \(\mathrm{C_2H_5OH+Na\to C_2H_5ONa}\) (B), and \(\mathrm{C_2H_5OH+PCl_5\to C_2H_5Cl}\) (C).

B and C then react by Williamson synthesis: \(\mathrm{C_2H_5ONa+C_2H_5Cl\to C_2H_5OC_2H_5+NaCl}\). So A, B, C = ethanol, sodium ethoxide, chloroethane.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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The compound A on treatment with Na gives B, and with PCl_5 gives C. B and C react together to give diethyl ether. A, B and C are in the order

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