1. A₀+√(A²+B²) 2. √(A²+B²) 3. √(A₀²+(A+B)²) 4. A+B

Answer: 2. √(A²+B²) The constant A₀ only shifts the mean position. The oscillating part is Asinω t+Bcosω t . Write it as Csin(ω t+φ) with Ccosφ=A,\ Csinφ=B . Then C=√(A²+B²) . So the amplitude is √(A²+B²) .

Topic: SHM and its equation, phase· Oscillations and Waves

The displacement of a particle executing simple harmonic motion is given byy = A_0 + Aω t + Bω t.Then the amplitude of its oscillation is given by :

1. \(A_0+\sqrt{A^2+B^2}\)

2. \(\sqrt{A^2+B^2}\)

3. \(\sqrt{A_0^2+(A+B)^2}\)

4. \(A+B\)

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Answer: 2. \(\sqrt{A^2+B^2}\)

The constant \(A_0\) only shifts the mean position. The oscillating part is \(A\sin\omega t+B\cos\omega t\).

Write it as \(C\sin(\omega t+\phi)\) with \(C\cos\phi=A,\ C\sin\phi=B\). Then \(C=\sqrt{A^2+B^2}\).

So the amplitude is \(\sqrt{A^2+B^2}\).

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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The displacement of a particle executing simple harmonic motion is given byy = A_0 + Aω t + Bω t.Then the amplitude of its oscillation is given by :

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