1. π rad 2. 3π/2 rad 3. π/2 rad 4. zero

The phase difference between displacement and acceleration of a particle in a simple harmonic motion is :

1. \(\pi\) rad

2. \(\frac{3\pi}{2}\) rad

3. \(\frac{\pi}{2}\) rad

4. zero

Doubtly Asked 30 Oct 2026 NEET UG 2020 Practice test neet Save WhatsApp Report

Best answer

Answer: 1. \(\pi\) rad

For SHM, \(x=A\sin\omega t\), and acceleration \(a=-\omega^2x\).

The negative sign means acceleration is always opposite in direction to displacement, so the phase difference is \(\pi\) rad.

Answer: option 1.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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