If x=5≤ft(π t+π/3)m represents the motion of a particle executing simple harmonic motion, the amplitude and time period of motion, respectively, are :

1. 5 m, 1 s

2. 5 cm, 2 s

3. 5 m, 2 s

4. 5 cm, 1 s

Doubtly Asked 30 Oct 2026 NEET UG 2024 Practice test neet Save WhatsApp Report

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Answer: 3. 5 m, 2 s

Key idea: Compare with the standard SHM form \(x=A\sin(\omega t+\phi)\).

Here \(A=5\) m and \(\omega=\pi\) rad/s. Time period \(T=\frac{2\pi}{\omega}=\frac{2\pi}{\pi}=2\) s.

Amplitude 5 m, period 2 s: option 3. The options with cm are wrong because the equation is given in metres.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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