Skip to content
doubtly

1 answer

Best answer

Answer: 2. \(RCOO^-Mg^+X\)

Key idea: a Grignard reagent adds to \(\mathrm{CO_2}\) to give a magnesium carboxylate salt, which acid hydrolysis converts to the acid.

\(\mathrm{RMgX + O{=}C{=}O \to RCOO^-Mg^+X}\) (Y), then \(\mathrm{H_3O^+}\) gives \(\mathrm{RCOOH}\).

Y is the halomagnesium carboxylate, option 2. Option 1 would need two carboxylate groups on one Mg, but one \(\mathrm{RMgX}\) adds to one \(\mathrm{CO_2}\), and option 3 is what a ketone would give after further addition.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
Was this answer helpful?

Your answer

Log in or create a free account to answer this question.